int x = int.Parse("123");
How do i convert numbers in string format to int in c#?
You would use the Int32.Parse() method; however, this method will throw an exception if the string that is passed to it is not a valid sequence of characters that defines an integer.
One thing I like to do (and this method can be overloaded since it differs by parameter type as well as return type) is to take a string and an second parameter as a default value if it fails. You would then have something like:
int GetValue(string data, int defaultValue)
{
int result = defaultValue;
try { result = Int32.Parse(data); }
catch { }
return result;
}
Reply:Something like this should work for you
public int convertStringToInt(string strSource)
{
try
{
return int.Parse(strSource);
}
catch
{
return null;
}
}
Sunday, August 2, 2009
How to input a binary string bit by bit in C?
input a string array in the same way u do for integers.
char arr[20];
for(int a=0;a%26lt;=20;a++)
{
scanf("%c",%26amp;arr[a]);
}
How to input a binary string bit by bit in C?
Strait C? Not C++... boy it's been a long time!
I would recommend storing the values in a char array and then converting the result after it was all input.
#include %26lt;stdio.h%26gt;
char line[100];
printf("Enter Binay String");
fgets(line, sizeof(line), stdin);
Reply:Use cin in a for loop?
Reply:/* this code will promt u to enter d string until u press ENTER key.....
char ch;
char string[100];
int i=0;
while( ch != 13) // 13 is ascii value for "enter" or carriage return..
{
ch = getchar();
string[i]=ch;
i++;
}
char arr[20];
for(int a=0;a%26lt;=20;a++)
{
scanf("%c",%26amp;arr[a]);
}
How to input a binary string bit by bit in C?
Strait C? Not C++... boy it's been a long time!
I would recommend storing the values in a char array and then converting the result after it was all input.
#include %26lt;stdio.h%26gt;
char line[100];
printf("Enter Binay String");
fgets(line, sizeof(line), stdin);
Reply:Use cin in a for loop?
Reply:/* this code will promt u to enter d string until u press ENTER key.....
char ch;
char string[100];
int i=0;
while( ch != 13) // 13 is ascii value for "enter" or carriage return..
{
ch = getchar();
string[i]=ch;
i++;
}
How do i put a string into an array in c language?
declare it as an array
How do i put a string into an array in c language?
create a character array and copy the string into the array?
florist shop
How do i put a string into an array in c language?
create a character array and copy the string into the array?
florist shop
What is the easiest way to determine if a string is a number in c#?
Convert.ToInt32()
will convert char's and strings
I am trying to get
Int32.TryParse(Console.ReadLine(), System.Globalization.NumberStyles.Intege... IFormatProvider, out searchZip);
..to work but wtf is an IFormat provider and is there a simple version of one that I can use or make?
...what is the simplest way to do this?
for my purposes 99999 is a number and 99,999 is not a number. wererewoiy definately is not a number.
What is the easiest way to determine if a string is a number in c#?
public static bool IsNumeric(object Expression)
{
bool isNum;
double retNum;
isNum = Double.TryParse(Convert.ToString(Express... System.Globalization.NumberStyles.Any,Sy... out retNum );
return isNum;
}
Try this
will convert char's and strings
I am trying to get
Int32.TryParse(Console.ReadLine(), System.Globalization.NumberStyles.Intege... IFormatProvider, out searchZip);
..to work but wtf is an IFormat provider and is there a simple version of one that I can use or make?
...what is the simplest way to do this?
for my purposes 99999 is a number and 99,999 is not a number. wererewoiy definately is not a number.
What is the easiest way to determine if a string is a number in c#?
public static bool IsNumeric(object Expression)
{
bool isNum;
double retNum;
isNum = Double.TryParse(Convert.ToString(Express... System.Globalization.NumberStyles.Any,Sy... out retNum );
return isNum;
}
Try this
In C++ what is the easiest way to convert a string (std::string) to type int?
Lets say I have a String number
number="100"
whats the easiest way to conver this string into an int type
In C++ what is the easiest way to convert a string (std::string) to type int?
Use the standard library functions atoi (ascii to int), atof (float), or atol (long):
#include %26lt;stdlib.h%26gt;
int x = atoi("100");
float y = atof("100.1");
long z = atol("1000000");
Reply:Use streams:
string number= "100";
int x;
istringstream i(number);
if (i %26gt;%26gt; x)
cout%26lt;%26lt;x;
else
cout%26lt;%26lt;"Input not a number";
You have to include sstream for using this code. Now if you want to convert the number to float, just declare x as float and let the operator overloading do the rest.
I have provided you the code, now search net what does istringstream do and what magic can you perform with streams.
Reply:...
string s("999");
int n = atoi(s.c_str());
Reply:define it in a variable
Reply:I believe you could also simply "cast" the variable.
Here's the syntax: static_cast%26lt;type%26gt; (object)
static_cast%26lt;int%26gt;(x);
cout %26lt;%26lt; "x as integer" %26lt;%26lt; x %26lt;%26lt; endl;
I'm also pretty sure that there's no special include statements.
Hope that helps!
Rob
number="100"
whats the easiest way to conver this string into an int type
In C++ what is the easiest way to convert a string (std::string) to type int?
Use the standard library functions atoi (ascii to int), atof (float), or atol (long):
#include %26lt;stdlib.h%26gt;
int x = atoi("100");
float y = atof("100.1");
long z = atol("1000000");
Reply:Use streams:
string number= "100";
int x;
istringstream i(number);
if (i %26gt;%26gt; x)
cout%26lt;%26lt;x;
else
cout%26lt;%26lt;"Input not a number";
You have to include sstream for using this code. Now if you want to convert the number to float, just declare x as float and let the operator overloading do the rest.
I have provided you the code, now search net what does istringstream do and what magic can you perform with streams.
Reply:...
string s("999");
int n = atoi(s.c_str());
Reply:define it in a variable
Reply:I believe you could also simply "cast" the variable.
Here's the syntax: static_cast%26lt;type%26gt; (object)
static_cast%26lt;int%26gt;(x);
cout %26lt;%26lt; "x as integer" %26lt;%26lt; x %26lt;%26lt; endl;
I'm also pretty sure that there's no special include statements.
Hope that helps!
Rob
C++ codehow to input data into string like from file and than search for particular word in the string.?Thanks
if U have a file called f.txt for example U can make th following
freopen("f.txt","rt",stdin);
string s = "";
getline(cin,s); // this will read a line from the file
//now to search for a word use
s.strstr("Ur word"); // will return -1 in case the string is not found and the index of the start of the word otherwise
Regards,
freopen("f.txt","rt",stdin);
string s = "";
getline(cin,s); // this will read a line from the file
//now to search for a word use
s.strstr("Ur word"); // will return -1 in case the string is not found and the index of the start of the word otherwise
Regards,
Friday, July 31, 2009
How do u implement string functions using pointers in C?
i need a sample program involving strcpy n strcat
How do u implement string functions using pointers in C?
#include %26lt;stdio.h%26gt;
#include %26lt;string.h%26gt;
main() {
char* a = "hello ";//a is a pointer to a string "hello "
char* b = "world";//b is a pointer to a string "world"
char string1[strlen(a)+strlen(b)+1];//string1 is a pointer to a string of characters
strcpy(string1, a);//string1 now cantains a "hello " string
printf("%s\n", string1);
strcat(string1, b);//string1 now cantains hello world
printf("%s\n", string1);
}
Reply:The code example by jericbryledy is incorrect because no space has been allocated for string1 to contain the copied characters.
use malloc to provide space for the copied characters.
string1 = (char *)malloc(sizeof(char) * (strlen(a) + 1));
strcpy(string1, a);
sympathy flowers
How do u implement string functions using pointers in C?
#include %26lt;stdio.h%26gt;
#include %26lt;string.h%26gt;
main() {
char* a = "hello ";//a is a pointer to a string "hello "
char* b = "world";//b is a pointer to a string "world"
char string1[strlen(a)+strlen(b)+1];//string1 is a pointer to a string of characters
strcpy(string1, a);//string1 now cantains a "hello " string
printf("%s\n", string1);
strcat(string1, b);//string1 now cantains hello world
printf("%s\n", string1);
}
Reply:The code example by jericbryledy is incorrect because no space has been allocated for string1 to contain the copied characters.
use malloc to provide space for the copied characters.
string1 = (char *)malloc(sizeof(char) * (strlen(a) + 1));
strcpy(string1, a);
sympathy flowers
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